2-3x+x^2+y(-2x^2+4x-1)+y^2(2x-3)=0

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Solution for 2-3x+x^2+y(-2x^2+4x-1)+y^2(2x-3)=0 equation: 


Simplifying
2 + -3x + x2 + y(-2x2 + 4x + -1) + y2(2x + -3) = 0

Reorder the terms:
2 + -3x + x2 + y(-1 + 4x + -2x2) + y2(2x + -3) = 0
2 + -3x + x2 + (-1 * y + 4x * y + -2x2 * y) + y2(2x + -3) = 0

Reorder the terms:
2 + -3x + x2 + (4xy + -2x2y + -1y) + y2(2x + -3) = 0
2 + -3x + x2 + (4xy + -2x2y + -1y) + y2(2x + -3) = 0

Reorder the terms:
2 + -3x + x2 + 4xy + -2x2y + -1y + y2(-3 + 2x) = 0
2 + -3x + x2 + 4xy + -2x2y + -1y + (-3 * y2 + 2x * y2) = 0

Reorder the terms:
2 + -3x + x2 + 4xy + -2x2y + -1y + (2xy2 + -3y2) = 0
2 + -3x + x2 + 4xy + -2x2y + -1y + (2xy2 + -3y2) = 0

Reorder the terms:
2 + -3x + 4xy + 2xy2 + x2 + -2x2y + -1y + -3y2 = 0

Solving
2 + -3x + 4xy + 2xy2 + x2 + -2x2y + -1y + -3y2 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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